the diagram shows two balls before they collide. what is the momentum of the system after the collision? 0.0…

the diagram shows two balls before they collide. what is the momentum of the system after the collision? 0.0 kg·m/s 0.2 kg·m/s 0.3 kg·m/s 0.4 kg·m/s m₁ = 0.6 kg m₂ = 0.5 kg v₁ = 0.5 m/s v₂ = -0.2 m/s

the diagram shows two balls before they collide. what is the momentum of the system after the collision? 0.0 kg·m/s 0.2 kg·m/s 0.3 kg·m/s 0.4 kg·m/s m₁ = 0.6 kg m₂ = 0.5 kg v₁ = 0.5 m/s v₂ = -0.2 m/s

Answer

Explanation:

Step1: Calculate initial momentum of first ball

$p_1 = m_1v_1=0.6\times0.5 = 0.3\ kg\cdot m/s$

Step2: Calculate initial momentum of second ball

$p_2 = m_2v_2=0.5\times(- 0.2)=-0.1\ kg\cdot m/s$

Step3: Calculate total initial momentum

$p_{total - initial}=p_1 + p_2=0.3+( - 0.1)=0.2\ kg\cdot m/s$

Step4: Apply conservation of momentum

According to the law of conservation of momentum, the total momentum of a closed - system before and after a collision is the same. So $p_{total - final}=p_{total - initial}=0.2\ kg\cdot m/s$

Answer:

$0.2\ kg\cdot m/s$