the diagram shows two balls before they collide. what is the momentum of the system after the collision? 0.0…

the diagram shows two balls before they collide. what is the momentum of the system after the collision? 0.0 kg·m/s 0.2 kg·m/s 0.3 kg·m/s 0.4 kg·m/s m₁ = 0.6 kg v₁ = 0.5 m/s m₂ = 0.5 kg v₂ = -0.2 m/s

the diagram shows two balls before they collide. what is the momentum of the system after the collision? 0.0 kg·m/s 0.2 kg·m/s 0.3 kg·m/s 0.4 kg·m/s m₁ = 0.6 kg v₁ = 0.5 m/s m₂ = 0.5 kg v₂ = -0.2 m/s

Answer

Explanation:

Step1: Recall the law of conservation of momentum

The total momentum before the collision is equal to the total momentum after the collision. The formula for momentum is $p = mv$, and the total initial - momentum $p_{total - initial}=m_1v_1 + m_2v_2$.

Step2: Calculate the initial total momentum

Substitute $m_1 = 0.6\ kg$, $v_1=0.5\ m/s$, $m_2 = 0.5\ kg$, and $v_2=- 0.2\ m/s$ into the formula $p_{total - initial}=m_1v_1 + m_2v_2$. [ \begin{align*} p_{total - initial}&=(0.6\ kg\times0.5\ m/s)+(0.5\ kg\times(-0.2\ m/s))\ &=0.3\ kg\cdot m/s-0.1\ kg\cdot m/s\ &=0.2\ kg\cdot m/s \end{align*} ] Since $p_{total - final}=p_{total - initial}$, the momentum of the system after the collision is $0.2\ kg\cdot m/s$.

Answer:

$0.2\ kg\cdot m/s$