the diagrams below show three pure samples of gas in identical closed, rigid containers. each sample…

the diagrams below show three pure samples of gas in identical closed, rigid containers. each sample contains the same number of gas particles. the particles in gas b and gas c are moving at the same average speed, while the particles in gas a are moving at a higher average speed. each particle in gas a and gas c has the same mass, while each particle in gas b has less mass. order the samples by their gas pressures. higher gas pressure gas c gas a gas b

the diagrams below show three pure samples of gas in identical closed, rigid containers. each sample contains the same number of gas particles. the particles in gas b and gas c are moving at the same average speed, while the particles in gas a are moving at a higher average speed. each particle in gas a and gas c has the same mass, while each particle in gas b has less mass. order the samples by their gas pressures. higher gas pressure gas c gas a gas b

Answer

Explanation:

Step1: Recall pressure - kinetic energy relation

Pressure of a gas is related to the kinetic energy of its particles. Kinetic energy formula is $K = \frac{1}{2}mv^{2}$, where $m$ is mass and $v$ is velocity.

Step2: Analyze gas A

Gas A particles have higher average speed than B and C. Particles of A and C have same mass. Since $K=\frac{1}{2}mv^{2}$, gas A particles have higher kinetic energy than C (due to higher speed) and higher kinetic energy than B (due to both higher speed and higher mass). Higher kinetic - energy means more forceful collisions with the container walls, so higher pressure.

Step3: Analyze gas C and B

Particles of B and C have same speed, but C particles have more mass. Using $K=\frac{1}{2}mv^{2}$, C particles have higher kinetic energy than B particles. So C has higher pressure than B.

Answer:

gas A, gas C, gas B