drag each tile to the correct box. adam takes a bus on a school field trip. the bus route is split into the…

drag each tile to the correct box. adam takes a bus on a school field trip. the bus route is split into the five legs listed in the table. find the average velocity for each leg of the trip. then arrange the legs of the trip from highest velocity to lowest.\n| leg | distance (km) | time (min) |\n| ---- | ---- | ---- |\n| a | 18 | 9 |\n| b | 25 | 15 |\n| c | 24 | 8 |\n| d | 48 | 12 |\n| e | 15 | 7 |
Answer
Answer:
The average velocities in km/min and the order from highest to lowest are: D: 4 km/min C: 3 km/min A: 2 km/min B: $\frac{5}{3}\approx1.67$ km/min E: $\frac{15}{7}\approx2.14$ km/min Order: D, C, E, A, B
Explanation:
Step1: Recall velocity formula
Velocity $v=\frac{d}{t}$, where $d$ is distance and $t$ is time.
Step2: Calculate velocity for leg A
$v_A=\frac{18}{9}=2$ km/min
Step3: Calculate velocity for leg B
$v_B=\frac{25}{15}=\frac{5}{3}\approx1.67$ km/min
Step4: Calculate velocity for leg C
$v_C=\frac{24}{8}=3$ km/min
Step5: Calculate velocity for leg D
$v_D=\frac{48}{12}=4$ km/min
Step6: Calculate velocity for leg E
$v_E=\frac{15}{7}\approx2.14$ km/min
Step7: Arrange in order
Compare the values: $4>3 > 2.14>2>1.67$, so the order is D, C, E, A, B.