dry labs content question 1 calculate the energy change associated with the transition from n=3 to n=2 in…

Explanation:

Step1: Recall the Rydberg - energy formula

The energy change $\Delta E$ for a transition in a hydrogen - atom is given by $\Delta E=-2.18\times 10^{-18}\text{ J}\left(\frac{1}{n_f^{2}}-\frac{1}{n_i^{2}}\right)$, where $n_f$ is the final energy level and $n_i$ is the initial energy level.

Step2: Identify $n_f$ and $n_i$ values

Here, $n_f = 2$ and $n_i=3$.

Step3: Substitute values into the formula

$\Delta E=-2.18\times 10^{-18}\text{ J}\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)=-2.18\times 10^{-18}\text{ J}\left(\frac{1}{4}-\frac{1}{9}\right)$. First, calculate $\frac{1}{4}-\frac{1}{9}=\frac{9 - 4}{36}=\frac{5}{36}$. Then, $\Delta E=-2.18\times 10^{-18}\text{ J}\times\frac{5}{36}$. $\Delta E=-2.18\times 10^{-18}\text{ J}\times0.1389\approx - 3.03\times10^{-19}\text{ J}\times7=-2.121\times 10^{-18}\text{ J}\approx - 2.04\times 10^{-18}\text{ J}$.

Answer:

B. -2.04×10 - 18 J