a dust particle (m = 5.0x10^(-8)kg) that carries charge q = 8.0x10^(-6)c is placed in between two parallel…

a dust particle (m = 5.0x10^(-8)kg) that carries charge q = 8.0x10^(-6)c is placed in between two parallel plates that are equally but oppositely charged at a distance of 4.0cm from the (-) plate. the strength of this constant (uniform) electric field is e = 12,500 n/c. find the work done as the field pushes q toward the (-) plate through that distance of 4.0cm.\n0.004j\n4.0j\n0.524j\n400j
Answer
Explanation:
Step1: Recall work - electric field formula
The formula for work done $W$ by an electric field on[Client Connection Error]