what is the electric field at a point 0.300 m to the right of a -4.77*10^-9 c charge? include a + or - sign…

what is the electric field at a point 0.300 m to the right of a -4.77*10^-9 c charge? include a + or - sign to indicate the direction of the field. (unit = n/c)

what is the electric field at a point 0.300 m to the right of a -4.77*10^-9 c charge? include a + or - sign to indicate the direction of the field. (unit = n/c)

Answer

Explanation:

Step1: Write the formula for electric field

The formula for the electric field due to a point charge is (E = k\frac{q}{r^{2}}), where (k = 9\times10^{9}\ N\cdot m^{2}/C^{2}), (q) is the charge, and (r) is the distance from the charge.

Step2: Substitute the given values

Given (q=- 4.77\times10^{-9}\ C) and (r = 0.300\ m). Substitute into the formula: (E=(9\times10^{9})\frac{-4.77\times10^{-9}}{(0.300)^{2}}) First, calculate ((0.300)^{2}=0.09) Then, ((9\times10^{9})\times(-4.77\times10^{-9})=-42.93) Now, (E=\frac{-42.93}{0.09})

Step3: Calculate the value of (E)

(E=- 477\ N/C)

Answer:

(-477)