what is the electric potential energy of a charge that experiences a force of 3.6×10⁻⁴ n when it is 9.8×10⁻⁵…

what is the electric potential energy of a charge that experiences a force of 3.6×10⁻⁴ n when it is 9.8×10⁻⁵ m from the source of the electric field?\n3.5×10⁻⁸ j\n4.6×10⁻⁴ j\n2.7×10⁻¹ j\n3.7×10⁰ j

what is the electric potential energy of a charge that experiences a force of 3.6×10⁻⁴ n when it is 9.8×10⁻⁵ m from the source of the electric field?\n3.5×10⁻⁸ j\n4.6×10⁻⁴ j\n2.7×10⁻¹ j\n3.7×10⁰ j

Answer

Explanation:

Step1: Recall the formula for electric - potential energy

The formula for electric - potential energy $U = Fd$ (where $F$ is the force on the charge and $d$ is the distance from the source of the electric field).

Step2: Substitute the given values

Given $F = 3.6\times10^{-4}\text{ N}$ and $d=9.8\times 10^{-5}\text{ m}$. Then $U=(3.6\times 10^{-4})\times(9.8\times 10^{-5})$. Using the rule of exponents $a^m\times a^n=a^{m + n}$, we have $U=(3.6\times9.8)\times10^{-4+( - 5)}=35.28\times10^{-9}\text{ J}$. Rounding to two significant figures and converting to scientific notation, $U\approx3.5\times 10^{-8}\text{ J}$.

Answer:

$3.5\times 10^{-8}\text{ J}$ (corresponding to the first option in the multiple - choice list)