what is the electrical force between q1 and q2? recall that k = 8.99×10^9 n·m²/c². q1 = +6 c q2 = -4 c q3 =…

Explanation:

Step1: Identify Coulomb's law formula

The formula for the electrical force between two charges is $F = k\frac{|q_1q_2|}{r^{2}}$, where $k = 8.99\times 10^{9}\ N\cdot\frac{m^{2}}{C^{2}}$, $q_1$ and $q_2$ are the charges, and $r$ is the distance between them.

Step2: Substitute the given values

We have $q_1 = 6\ C$, $q_2=- 4\ C$, and $r = 2\ m$. First, calculate the product of the magnitudes of the charges $|q_1q_2|=|6\times(-4)| = 24\ C^{2}$, and $r^{2}=2^{2}=4\ m^{2}$.

Step3: Calculate the force

Substitute into the formula: $F=8.99\times 10^{9}\frac{24}{4}\ N$. $F = 8.99\times10^{9}\times6\ N=53.94\times 10^{9}\ N\approx5.4\times 10^{10}\ N$. Since the charges have opposite - signs, the force is attractive, so $F=- 5.4\times 10^{10}\ N$.

Answer:

$-5.4\times 10^{10}\ N$