what is the energy of a photon with a frequency of 3.6×10^{15} hz? plancks constant is 6.63×10^{-34}…

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = h\nu$, where $E$ is the energy, $h$ is Planck's constant, and $\nu$ is the frequency.

Step2: Substitute given values

We have $h = 6.63\times10^{-34}\ J\cdot s$ and $\nu=3.6\times 10^{15}\ Hz$. Then $E=(6.63\times 10^{-34}\ J\cdot s)\times(3.6\times 10^{15}\ Hz)$.

Step3: Calculate the result

Using the rule of exponents $a^m\times a^n=a^{m + n}$, we get $E=(6.63\times3.6)\times10^{-34 + 15}\ J=23.868\times10^{-19}\ J\approx2.4\times 10^{-18}\ J$.

Answer:

$2.4\times 10^{-18}\ J$