what is the energy of a photon with a frequency of 2.2×10^{16} hz? plancks constant is 6.63×10^{-34}…

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = h\nu$, where $E$ is the energy, $h$ is Planck's constant, and $\nu$ is the frequency.

Step2: Substitute given values

We have $h = 6.63\times10^{-34}\text{ J}\cdot\text{s}$ and $\nu=2.2\times 10^{16}\text{ Hz}$. So $E=(6.63\times 10^{-34}\text{ J}\cdot\text{s})\times(2.2\times 10^{16}\text{ Hz})$.

Step3: Perform multiplication

Using the rule of exponents $a^m\times a^n=a^{m + n}$, we get $E=(6.63\times2.2)\times10^{-34 + 16}\text{ J}$. $6.63\times2.2 = 14.586$, and $-34+16=-18$. So $E = 14.586\times10^{-18}\text{ J}$. Rounding to one - significant digit and adjusting the exponent, $E\approx1.5\times 10^{-17}\text{ J}$.

Answer:

A. $1.5\times 10^{-17}\text{ J}$