what is the energy of a photon with a frequency of 1.7×10^{17} hz? plancks constant is 6.63×10^{-34}…

Answer:

A. $1.1\times 10^{-16}\text{ J}$

Explanation:

Step1: Recall the energy - frequency formula

The energy of a photon is given by $E = h\nu$, where $E$ is the energy, $h$ is Planck's constant, and $\nu$ is the frequency.

Step2: Substitute the given values

We are given that $h = 6.63\times 10^{-34}\text{ J}\cdot\text{s}$ and $\nu=1.7\times 10^{17}\text{ Hz}$. $E=(6.63\times 10^{-34}\text{ J}\cdot\text{s})\times(1.7\times 10^{17}\text{ Hz})$

Step3: Perform the multiplication

Using the rule of exponents $a^m\times a^n=a^{m + n}$, we have $E=(6.63\times1.7)\times10^{-34 + 17}\text{ J}$. $6.63\times1.7 = 11.271$, and $-34+17=-17$. So $E = 11.271\times 10^{-17}\text{ J}$.

Step4: Convert to scientific notation

$11.271\times 10^{-17}\text{ J}=1.1271\times 10^{-16}\text{ J}\approx1.1\times 10^{-16}\text{ J}$