energy transformation: pe - ke\nif an object has 100 joules of potential energy (pe) at the top of a ramp…

energy transformation: pe - ke\nif an object has 100 joules of potential energy (pe) at the top of a ramp, how much kinetic energy (ke) will there be at the other two locations indicated, half - way down the ramp and at the bottom the ramp?\na 0j and 50j\nb 50j and 0j\nc 50j and 100j\nd 100j and 50j\nin the first question, we described an energy transformation in a situation without friction. in reality, we almost always must contend with friction when analyzing energy transformations. how would the values change and why?

energy transformation: pe - ke\nif an object has 100 joules of potential energy (pe) at the top of a ramp, how much kinetic energy (ke) will there be at the other two locations indicated, half - way down the ramp and at the bottom the ramp?\na 0j and 50j\nb 50j and 0j\nc 50j and 100j\nd 100j and 50j\nin the first question, we described an energy transformation in a situation without friction. in reality, we almost always must contend with friction when analyzing energy transformations. how would the values change and why?

Answer

Explanation:

Step1: Apply conservation of mechanical energy

In the absence of friction, the total mechanical energy (sum of potential energy PE and kinetic energy KE) is conserved. At the top of the ramp, total mechanical energy $E = PE+KE=100 + 0=100\ J$.

Step2: Calculate KE at point B

At point B, $PE = 50\ J$. Since $E=PE + KE$ and $E = 100\ J$, then $KE=E - PE=100 - 50=50\ J$.

Step3: Calculate KE at point C

At the bottom of the ramp, $PE = 0\ J$. Since $E=PE + KE$ and $E = 100\ J$, then $KE=E - PE=100 - 0=100\ J$.

Answer:

C. 50J and 100J