the equation $h(t)= - 9.8t^{2}+100$ represents the relationship of the height, in meters, over time, in…

the equation $h(t)= - 9.8t^{2}+100$ represents the relationship of the height, in meters, over time, in seconds, of an object dropped from the height of 100 meters. what is the height of the object 2.5 seconds after it was dropped? (1 point)\n138.75 meters\n100 meters\n3.19 meters\n38.75 meters

the equation $h(t)= - 9.8t^{2}+100$ represents the relationship of the height, in meters, over time, in seconds, of an object dropped from the height of 100 meters. what is the height of the object 2.5 seconds after it was dropped? (1 point)\n138.75 meters\n100 meters\n3.19 meters\n38.75 meters

Answer

Explanation:

Step1: Substitute t value

Substitute $t = 2.5$ into $h(t)=-9.8t^{2}+100$. $h(2.5)=-9.8\times(2.5)^{2}+100$

Step2: Calculate $(2.5)^{2}$

$(2.5)^{2}=2.5\times2.5 = 6.25$ $h(2.5)=-9.8\times6.25 + 100$

Step3: Calculate $-9.8\times6.25$

$-9.8\times6.25=-61.25$ $h(2.5)=-61.25 + 100$

Step4: Calculate the sum

$h(2.5)=38.75$

Answer:

38.75 meters