the equation that gives the distance fallen, s, by an object in time, t, assuming that the object starts at…

the equation that gives the distance fallen, s, by an object in time, t, assuming that the object starts at rest is: s = 1/2 * g * t^2 where g is the acceleration of gravity. solve the equation for time. a t = sqrt(4s/g) b t = 2s/g c t = sqrt(g/(2s)) d t = sqrt(2s/g)

the equation that gives the distance fallen, s, by an object in time, t, assuming that the object starts at rest is: s = 1/2 * g * t^2 where g is the acceleration of gravity. solve the equation for time. a t = sqrt(4s/g) b t = 2s/g c t = sqrt(g/(2s)) d t = sqrt(2s/g)

Answer

Explanation:

Step1: Isolate $t^2$

Starting with $s=\frac{1}{2}gt^{2}$, multiply both sides by $2$ to get $2s = gt^{2}$. Then divide both sides by $g$: $t^{2}=\frac{2s}{g}$.

Step2: Solve for $t$

Take the square - root of both sides. Since $t$ represents time and is non - negative in this context, $t=\sqrt{\frac{2s}{g}}$.

Answer:

D. $t = \sqrt{\frac{2s}{g}}$