which equation is most likely used to determine the acceleration from a velocity vs. time graph?\n$a =…

which equation is most likely used to determine the acceleration from a velocity vs. time graph?\n$a = \\frac{t}{\\delta v}$\n$m = \\frac{v_2 - v_1}{x_2 - x_1}$\n$a = \\frac{\\delta v}{m}$\n$m = \\frac{x_2 - x_1}{v_2 - v_1}$

which equation is most likely used to determine the acceleration from a velocity vs. time graph?\n$a = \\frac{t}{\\delta v}$\n$m = \\frac{v_2 - v_1}{x_2 - x_1}$\n$a = \\frac{\\delta v}{m}$\n$m = \\frac{x_2 - x_1}{v_2 - v_1}$

Answer

Explanation:

Step1: Recall acceleration formula

Acceleration $a$ is the rate of change of velocity. On a velocity - time graph, acceleration is the slope of the graph. The formula for slope $m$ of a line between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $m=\frac{y_2 - y_1}{x_2 - x_1}$. In a velocity - time graph, $y$ represents velocity $v$ and $x$ represents time $t$. So acceleration $a=\frac{\Delta v}{\Delta t}$, which is equivalent to the slope formula for a velocity - time graph.

Step2: Analyze options

The first option $a = \frac{t}{\Delta v}$ is incorrect as it is the inverse of the correct relationship. The third option $a=\frac{\Delta v}{m}$ is the formula for acceleration from Newton's second law $F = ma$ ($a=\frac{F}{m}$ where $F=\Delta v$ in some non - standard context which is not relevant here). The fourth option $m=\frac{x_2 - x_1}{v_2 - v_1}$ is the inverse of the slope formula for a velocity - time graph. The second option $m=\frac{v_2 - v_1}{x_2 - x_1}$ (where $x$ is time $t$) represents the slope of the velocity - time graph which is acceleration.

Answer:

$m=\frac{v_2 - v_1}{x_2 - x_1}$ (assuming $x$ represents time $t$)