which equation could be rearranged to calculate the frequency of a wave?\n○ wavelength = frequency/speed\n○…

Explanation:

Step1: Recall the wave speed formula

The basic formula relating wave speed ((v)), wavelength ((\lambda)), and frequency ((f)) is (v = \lambda \times f).

Step2: Rearrange to solve for frequency

To find the formula that can be rearranged to calculate frequency, we start with (v=\lambda f). Dividing both sides by (\lambda) gives (f=\frac{v}{\lambda}), or in terms of the variables here (speed, wavelength, frequency), (frequency=\frac{speed}{wavelength})? Wait, no, wait. Wait the standard formula is (v = f\lambda), so solving for (f) gives (f=\frac{v}{\lambda}), which is (frequency=\frac{speed}{wavelength})? But looking at the options, let's check each:

1. (wavelength = \frac{frequency}{speed}): Rearranging (v = f\lambda) to (\lambda=\frac{v}{f}), so this is wrong.
2. (frequency=\frac{wavelength}{speed}): From (v = f\lambda), (f=\frac{v}{\lambda}), so this is wrong.
3. (wavelength=\frac{speed}{frequency}): From (v = f\lambda), divide both sides by (f): (\lambda=\frac{v}{f}), which is (wavelength=\frac{speed}{frequency}) (since (v) is speed). So if we start with this equation, we can rearrange it to solve for frequency. Let's see: (\lambda=\frac{v}{f}) multiply both sides by (f): (\lambda f = v), then divide by (\lambda): (f=\frac{v}{\lambda}), which is frequency. So this equation can be rearranged to find frequency.
4. (frequency = speed \times wavelength): From (v = f\lambda), this would imply (f = v\lambda), which is wrong.

So the correct equation that can be rearranged to calculate frequency is (wavelength=\frac{speed}{frequency}) (the third option), because starting from (\lambda=\frac{v}{f}), we can solve for (f) as (f=\frac{v}{\lambda}).

Answer:

The equation that can be rearranged to calculate the frequency of a wave is the one where (wavelength = \frac{speed}{frequency}) (the third option, i.e., the option with "wavelength = speed/frequency").