what is the equivalent resistance in this circuit? ω what is the current in this circuit? a 45 v 2.0 ω 3.0 ω…

Explanation:

Step1: Calculate equivalent resistance

Since the resistors are in series, we use the formula for equivalent - resistance of resistors in series $R_{eq}=R_1 + R_2+R_3+R_4$. Here, $R_1 = 2.0\Omega$, $R_2 = 3.0\Omega$, $R_3 = 4.0\Omega$, $R_4 = 6.0\Omega$. So, $R_{eq}=2.0 + 3.0+4.0 + 6.0=15.0\Omega$.

Step2: Calculate the current

We use Ohm's law $I=\frac{V}{R_{eq}}$. Given $V = 45V$ and $R_{eq}=15.0\Omega$. Then $I=\frac{45}{15}=3A$.

Answer:

Equivalent resistance: $15.0\Omega$ Current: $3A$