what is the equivalent resistance of the two resistors? r1 200 ω r2 250 ω req = ? ω

Explanation:

Step1: Recall parallel - resistance formula

For two resistors $R_1$ and $R_2$ in parallel, the equivalent resistance $R_{eq}$ is given by $\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}$.

Step2: Substitute the given values

Here, $R_1 = 200\Omega$ and $R_2=250\Omega$. So, $\frac{1}{R_{eq}}=\frac{1}{200}+\frac{1}{250}$. First, find a common denominator. The common denominator of 200 and 250 is 1000. Then $\frac{1}{200}+\frac{1}{250}=\frac{5}{1000}+\frac{4}{1000}=\frac{5 + 4}{1000}=\frac{9}{1000}$.

Step3: Solve for $R_{eq}$

Since $\frac{1}{R_{eq}}=\frac{9}{1000}$, then $R_{eq}=\frac{1000}{9}\approx111.11\Omega$.

Answer:

$\frac{1000}{9}\Omega$ (or approximately $111.11\Omega$)