1. eric drops a 2.2 kg water balloon that falls a distance of 14.7 m off the top of a building. what is the…

1. eric drops a 2.2 kg water balloon that falls a distance of 14.7 m off the top of a building. what is the kinetic energy of the balloon at the bottom of its fall?

1. eric drops a 2.2 kg water balloon that falls a distance of 14.7 m off the top of a building. what is the kinetic energy of the balloon at the bottom of its fall?

Answer

Explanation:

Step1: Identify Energy Transformation

The water balloon is dropped, so initial kinetic energy ( KE_i = 0 ) (starts from rest). Gravitational potential energy (GPE) is converted to kinetic energy (KE) at the bottom (neglecting air resistance). The formula for GPE is ( GPE = mgh ), and at the bottom, ( KE_f = GPE_i ) (conservation of mechanical energy, ( KE_i + GPE_i = KE_f + GPE_f ), and ( GPE_f = 0 ) at the bottom, ( KE_i = 0 )).

Step2: Plug in Values

Mass ( m = 2.2 , \text{kg} ), height ( h = 14.7 , \text{m} ), gravitational acceleration ( g = 9.8 , \text{m/s}^2 ).
Calculate ( KE_f = mgh ).
Substitute: ( KE_f = 2.2 \times 9.8 \times 14.7 ).

Step3: Compute the Result

First, ( 2.2 \times 9.8 = 21.56 ).
Then, ( 21.56 \times 14.7 \approx 316.932 , \text{J} ).

Answer:

( \approx 317 , \text{J} ) (or more precisely ( 316.932 , \text{J} ))