how fast is a p - wave if it takes 71 seconds to travel 355 km through granite? your answer 4 points a p…

how fast is a p - wave if it takes 71 seconds to travel 355 km through granite? your answer 4 points a p - wave can travel 1.45 km/s through water. how long will it take for a p - wave to travel from the bottom of the ocean to the surface if the ocean depth is 4.3 km? give your answer in seconds. your answer 4 points the thud of a p - wave hits your house at 8:31 at night. at exactly 8:37 pm, the house begins to rumble from the s - wave arriving. what was the lag time? your answer 2 points the epicenter of an earthquake is 250 km away. you feel the thud of its p - wave with the velocity of 6.3 km/s. how many seconds later would you expect to feel the s - wave with the velocity of 4.8 km/s? your answer 6 points

how fast is a p - wave if it takes 71 seconds to travel 355 km through granite? your answer 4 points a p - wave can travel 1.45 km/s through water. how long will it take for a p - wave to travel from the bottom of the ocean to the surface if the ocean depth is 4.3 km? give your answer in seconds. your answer 4 points the thud of a p - wave hits your house at 8:31 at night. at exactly 8:37 pm, the house begins to rumble from the s - wave arriving. what was the lag time? your answer 2 points the epicenter of an earthquake is 250 km away. you feel the thud of its p - wave with the velocity of 6.3 km/s. how many seconds later would you expect to feel the s - wave with the velocity of 4.8 km/s? your answer 6 points

Answer

Explanation:

Step1: Recall velocity - distance - time formula

The formula for velocity $v=\frac{d}{t}$, where $v$ is velocity, $d$ is distance and $t$ is time.

Step2: Solve for the velocity of p - wave in granite

Given $d = 355$ km and $t=71$ s. Using $v=\frac{d}{t}$, we have $v=\frac{355}{71}$ km/s. $v = 5$ km/s

Step3: Solve for the time it takes for p - wave to travel through water

Given $v = 1.45$ km/s and $d = 4.3$ km. Rearranging the formula $v=\frac{d}{t}$ to $t=\frac{d}{v}$, we get $t=\frac{4.3}{1.45}\approx2.97$ s

Step4: Calculate the time - lag between p - wave and s - wave arrival for the house

The time of p - wave arrival is 8:31 pm and s - wave arrival is 8:37 pm. The time - lag $t=8:37 - 8:31=6$ minutes. Since 1 minute = 60 seconds, $t = 6\times60=360$ s

Step5: Calculate the time difference between p - wave and s - wave arrival from the epicenter

For the p - wave, using $t_p=\frac{d}{v_p}$, with $d = 250$ km and $v_p=6.3$ km/s, $t_p=\frac{250}{6.3}\approx39.68$ s. For the s - wave, using $t_s=\frac{d}{v_s}$, with $d = 250$ km and $v_s = 4.8$ km/s, $t_s=\frac{250}{4.8}\approx52.08$ s. The time difference $\Delta t=t_s - t_p=52.08 - 39.68 = 12.4$ s

Answer:

  1. 5 km/s
  2. 2.97 s
  3. 360 s
  4. 12.4 s