fill in the blank of the following free fall chart: (this chart goes down instead of across)\n\ntime\t0…

fill in the blank of the following free fall chart: (this chart goes down instead of across)\n\ntime\t0 sec\t7 sec\nacceleration\t10 m/s/s\t\nm/s/s\ninstantaneous velocity\t0 m/s\tm/s\naverage velocity\t0 m/s\tm/s\ndistance fallen\t0 m\tm

fill in the blank of the following free fall chart: (this chart goes down instead of across)\n\ntime\t0 sec\t7 sec\nacceleration\t10 m/s/s\t\nm/s/s\ninstantaneous velocity\t0 m/s\tm/s\naverage velocity\t0 m/s\tm/s\ndistance fallen\t0 m\tm

Answer

Explanation:

Step1: Determine acceleration

In free - fall near the surface of the Earth (neglecting air resistance), the acceleration due to gravity is constant. So, the acceleration at 7 sec is also $10\ m/s^2$.

Step2: Calculate instantaneous velocity

The formula for instantaneous velocity in free - fall is $v = v_0+at$. Here, $v_0 = 0\ m/s$, $a = 10\ m/s^2$, and $t = 7\ s$. So, $v=0 + 10\times7=70\ m/s$.

Step3: Calculate average velocity

The average velocity for an object with constant acceleration starting from rest is $\bar{v}=\frac{v_0 + v}{2}$. Since $v_0 = 0\ m/s$ and $v = 70\ m/s$, $\bar{v}=\frac{0 + 70}{2}=35\ m/s$.

Step4: Calculate distance fallen

The formula for distance fallen in free - fall is $d=v_0t+\frac{1}{2}at^2$. With $v_0 = 0\ m/s$, $a = 10\ m/s^2$, and $t = 7\ s$, we have $d=0\times7+\frac{1}{2}\times10\times7^2=245\ m$.

Answer:

Acceleration: $10\ m/s^2$ Instantaneous Velocity: $70\ m/s$ Average Velocity: $35\ m/s$ Distance Fallen: $245\ m$