6 fill in the blank 4 points what is the equivalent resistance of this circuit? type your answer... ω (round…

Answer:

Equivalent resistance: 134.7 $\Omega$ Current: 0.089 A

Explanation:

Step1: Calculate the parallel - resistance of $R_2$ and $R_3$

The formula for parallel resistance of two resistors $R_a$ and $R_b$ is $R_{ab}=\frac{R_a\times R_b}{R_a + R_b}$. Here, $R_2 = 3300\Omega$ and $R_3=90\Omega$. So, $R_{23}=\frac{3300\times90}{3300 + 90}=\frac{297000}{3390}\approx87.6\Omega$.

Step2: Calculate the equivalent resistance of the circuit

The equivalent resistance $R_{eq}$ of the circuit is the sum of $R_1$ and $R_{23}$ since $R_1$ is in series with the parallel - combination of $R_2$ and $R_3$. $R_{eq}=R_1+R_{23}=47 + 87.6=134.6\Omega\approx134.7\Omega$.

Step3: Calculate the current in the circuit

According to Ohm's law $I=\frac{V}{R}$, where $V = 12V$ and $R = R_{eq}=134.7\Omega$. So, $I=\frac{12}{134.7}\approx0.089A$.