1. fill in the table showing\n| nuclear decay particle | reaction symbol |\n| ---- | ---- |\n| alpha | |\n|…

1. fill in the table showing\n| nuclear decay particle | reaction symbol |\n| ---- | ---- |\n| alpha | |\n| | $_{-1}^{0}e$ |\n| | $_{-1}^{0}e$ |\n| positron | |\n2. balance the nuclear equations below.\n a. $_{90}^{229}th\rightarrow _{2}^{4}he + _____$\n b. $_{8}^{20}o\rightarrow _{9}^{20}f+_____$\n c. $_{47}^{104}ag\rightarrow _{-1}^{0}e+_____$\n d. $_{51}^{110}sb+_{-1}^{0}e\rightarrow_____$\n e. $_{94}^{240}pu\rightarrow _{2}^{4}he+_____$\n f. _____$\rightarrow _{-1}^{0}e + _{24}^{54}cr$\n g. $_{54}^{118}xe\rightarrow _{+1}^{0}e+_____$\n h. $_{80}^{141}nd+_{-1}^{0}e\rightarrow_____$\n3. write a balanced nuclear equation for each decay process indicated.\n a. the isotope th - 234 decays by an alpha emission.\n b. the isotope fe - 59 decays by a beta emission.\n c. the isotope c - 11 decays by an electron capture.\n d. the isotope tc - 99 decays by a positron emission.\n e. the isotope potassium - 40 decays to produce argon - 40.\n f. the isotope uranium - 232 decays to produce thorium - 228.\n g. the isotope cerium - 144 decays to produce praseodymium - 144.

1. fill in the table showing\n| nuclear decay particle | reaction symbol |\n| ---- | ---- |\n| alpha | |\n| | $_{-1}^{0}e$ |\n| | $_{-1}^{0}e$ |\n| positron | |\n2. balance the nuclear equations below.\n a. $_{90}^{229}th\rightarrow _{2}^{4}he + _____$\n b. $_{8}^{20}o\rightarrow _{9}^{20}f+_____$\n c. $_{47}^{104}ag\rightarrow _{-1}^{0}e+_____$\n d. $_{51}^{110}sb+_{-1}^{0}e\rightarrow_____$\n e. $_{94}^{240}pu\rightarrow _{2}^{4}he+_____$\n f. _____$\rightarrow _{-1}^{0}e + _{24}^{54}cr$\n g. $_{54}^{118}xe\rightarrow _{+1}^{0}e+_____$\n h. $_{80}^{141}nd+_{-1}^{0}e\rightarrow_____$\n3. write a balanced nuclear equation for each decay process indicated.\n a. the isotope th - 234 decays by an alpha emission.\n b. the isotope fe - 59 decays by a beta emission.\n c. the isotope c - 11 decays by an electron capture.\n d. the isotope tc - 99 decays by a positron emission.\n e. the isotope potassium - 40 decays to produce argon - 40.\n f. the isotope uranium - 232 decays to produce thorium - 228.\n g. the isotope cerium - 144 decays to produce praseodymium - 144.

Answer

Explanation:

Step1: Complete nuclear decay particle table

Alpha particle symbol is ( \ce{^4_2He} ); ( \ce{^0_{-1}e} ) is beta-minus; positron symbol is ( \ce{^0_{+1}e} ).

Step2: Balance nuclear equations (a-h)

For each, balance mass/atomic numbers: sum reactants = sum products.

Step3: Write balanced decay equations (a-g)

Identify decay type, apply mass/atomic number conservation.

Answer:

Nuclear Decay Particle Reaction Symbol
Alpha ( \ce{^4_2He} )
Beta (Beta-minus) ( \ce{^0_{-1}e} )
Beta (Beta-minus) ( \ce{^0_{-1}e} )
Positron ( \ce{^0_{+1}e} )

a. ( \ce{^{225}{88}Ra} ) b. ( \ce{^0{-1}e} ) c. ( \ce{^{104}{48}Cd} ) d. ( \ce{^{110}{50}Sn} ) e. ( \ce{^{236}{92}U} ) f. ( \ce{^{54}{23}V} ) g. ( \ce{^{118}{53}I} ) h. ( \ce{^{141}{79}Au} )

a. ( \ce{^{234}{90}Th -> ^4_2He + ^{230}{88}Ra} ) b. ( \ce{^{59}{26}Fe -> ^0{-1}e + ^{59}{27}Co} ) c. ( \ce{^{11}6C + ^0{-1}e -> ^{11}5B} ) d. ( \ce{^{99}{43}Tc -> ^0{+1}e + ^{99}{42}Mo} ) e. ( \ce{^{40}{19}K + ^0_{-1}e -> ^{40}{18}Ar} ) f. ( \ce{^{232}{92}U -> ^4_2He + ^{228}{90}Th} ) g. ( \ce{^{144}{58}Ce -> ^0_{-1}e + ^{144}_{59}Pr} )