find the acceleration of a car that goes from 32 m/s to 96 m/s in 8.0 seconds.\n-8.0 m/s/s\n4.0 m/s/s\n8.0…

find the acceleration of a car that goes from 32 m/s to 96 m/s in 8.0 seconds.\n-8.0 m/s/s\n4.0 m/s/s\n8.0 m/s/s\n12 m/s/s

find the acceleration of a car that goes from 32 m/s to 96 m/s in 8.0 seconds.\n-8.0 m/s/s\n4.0 m/s/s\n8.0 m/s/s\n12 m/s/s

Answer

Answer:

8.0 m/s/s

Explanation:

Step1: Recall acceleration formula

Acceleration $a = \frac{v_f - v_i}{t}$

Step2: Identify given values

$v_f = 96\ \text{m/s}$, $v_i = 32\ \text{m/s}$, $t = 8.0\ \text{s}$

Step3: Substitute values into formula

$a = \frac{96 - 32}{8.0} = \frac{64}{8.0}$

Step4: Calculate final value

$a = 8.0\ \text{m/s}^2$