a football is kicked vertically upward from a height of 3 feet with an initial speed of 70 feet per second…
a football is kicked vertically upward from a height of 3 feet with an initial speed of 70 feet per second. the formula h = 3 + 70t - 16t^2 describes the balls height above the ground, h, in feet, t seconds after it was kicked. use this formula to find the balls height 2 seconds after it was kicked. the balls height, 2 seconds after it was kicked, was feet.
Answer
Explanation:
Step1: Substitute t value
Substitute $t = 2$ into $h=3 + 70t-16t^{2}$. $h=3 + 70\times2-16\times2^{2}$
Step2: Calculate multiplications
Calculate $70\times2$ and $16\times2^{2}$. $70\times2 = 140$, $16\times2^{2}=16\times4 = 64$. So $h=3 + 140-64$.
Step3: Calculate addition and subtraction
$h=(3 + 140)-64=143-64 = 79$.
Answer:
79