force, mass, and acceleration\nmixed practice a\ninstructions use the correct formula to solve the following…

force, mass, and acceleration\nmixed practice a\ninstructions use the correct formula to solve the following problems. round all answers to the correct number of significant figures. show all your work.\n1. mass: 35 kg, force: 35 n\n2. mass: 625 kg, acceleration: 2.5 m/s²\n3. force: 12.75 n, acceleration: 4.33 m/s²\n4. calculate the mass of a curling stone that accelerates 1.33 m/s² when a curler applies 24.6 n before releasing the stone.\n5. calculate the net force required to accelerate a 8.45 kg bicycle 1.83 m/s².\n6. calculate the acceleration of a 48 gram model rocket if the rocket engine produce 4.75 n net upward thrust.\nchecksum 1736.94 the checksum is the unrounded total of all correctly and rounded answers in the shaded boxes

force, mass, and acceleration\nmixed practice a\ninstructions use the correct formula to solve the following problems. round all answers to the correct number of significant figures. show all your work.\n1. mass: 35 kg, force: 35 n\n2. mass: 625 kg, acceleration: 2.5 m/s²\n3. force: 12.75 n, acceleration: 4.33 m/s²\n4. calculate the mass of a curling stone that accelerates 1.33 m/s² when a curler applies 24.6 n before releasing the stone.\n5. calculate the net force required to accelerate a 8.45 kg bicycle 1.83 m/s².\n6. calculate the acceleration of a 48 gram model rocket if the rocket engine produce 4.75 n net upward thrust.\nchecksum 1736.94 the checksum is the unrounded total of all correctly and rounded answers in the shaded boxes

Answer

Explanation:

Step1: Recall Newton's second - law formula

The formula is $F = ma$, where $F$ is force, $m$ is mass and $a$ is acceleration. We can re - arrange it as $a=\frac{F}{m}$ and $m = \frac{F}{a}$.

Step2: Solve problem 1

Given $m = 35\ kg$ and $F = 35\ N$. Using $a=\frac{F}{m}$, we have $a=\frac{35\ N}{35\ kg}=1\ m/s^{2}$.

Step3: Solve problem 2

Given $m = 625\ kg$ and $a = 2.5\ m/s^{2}$. Using $F=ma$, we get $F=625\ kg\times2.5\ m/s^{2}=1562.5\ N$.

Step4: Solve problem 3

Given $F = 12.75\ N$ and $a = 4.33\ m/s^{2}$. Using $m=\frac{F}{a}$, we obtain $m=\frac{12.75\ N}{4.33\ m/s^{2}}\approx2.94\ kg$.

Step5: Solve problem 4

Given $F = 24.6\ N$ and $a = 1.33\ m/s^{2}$. Using $m=\frac{F}{a}$, we find $m=\frac{24.6\ N}{1.33\ m/s^{2}}\approx18.5\ kg$.

Step6: Solve problem 5

Given $m = 8.45\ kg$ and $a = 1.83\ m/s^{2}$. Using $F = ma$, we have $F=8.45\ kg\times1.83\ m/s^{2}\approx15.46\ N$.

Step7: Solve problem 6

First convert mass to SI units: $m = 48\ g=0.048\ kg$ and $F = 4.75\ N$. Using $a=\frac{F}{m}$, we get $a=\frac{4.75\ N}{0.048\ kg}\approx99.0\ m/s^{2}$.

Answer:

  1. $1\ m/s^{2}$
  2. $1562.5\ N$
  3. $2.94\ kg$
  4. $18.5\ kg$
  5. $15.46\ N$
  6. $99.0\ m/s^{2}$