the force of an object is equal to its mass multiplied by its acceleration\nnewtons 2nd law of motion\nf = m…

the force of an object is equal to its mass multiplied by its acceleration\nnewtons 2nd law of motion\nf = m * a\nnewton’s second law\n1. how much force is needed to accelerate a 1000 - kg car at a rate of 3 m/s²?\nanswer units\nn kg m/s²\n2. if a 70 - kg swimmer pushes off a pool wall with a force of 250 n, at what rate will the swimmer accelerate from the wall?\nanswer units\nn kg m/s²\nround to 2 decimals\n3. a weightlifter raises a 200 - kg barbell with an acceleration of 3 m/s². how much force does the weightlifter use to raise the barbell.\nanswer units\nn kg m/s²\n4. a dancer lifts his partner above his head with an acceleration of 2.5 m/s². the dancer exerts a force of 200 n. what is the mass of the partner?\nanswer units\nn kg m/s²\n2) create your own examples\nin the following space, create your own action / reaction examples.\ndescribe event force triangle\ndescribe event force triangle
Answer
Explanation:
Step1: Identify the formula
We use Newton's second - law formula $F = m\times a$, where $F$ is force in Newtons (N), $m$ is mass in kilograms (kg), and $a$ is acceleration in $m/s^{2}$.
Step2: Solve question 1
Given $m = 1000$ kg and $a=3$ $m/s^{2}$. Substitute into the formula: $F=m\times a = 1000\times3=3000$ N.
Step3: Solve question 2
Given $F = 250$ N and $m = 70$ kg. Rearrange the formula to $a=\frac{F}{m}$. Then $a=\frac{250}{70}\approx3.57$ $m/s^{2}$.
Step4: Solve question 3
Given $m = 200$ kg and $a = 3$ $m/s^{2}$. Using $F=m\times a$, we get $F=200\times3 = 600$ N.
Step5: Solve question 4
Given $F = 200$ N and $a=2.5$ $m/s^{2}$. Rearrange the formula to $m=\frac{F}{a}$. So $m=\frac{200}{2.5}=80$ kg.
Answer:
- 3000 N
- 3.57 $m/s^{2}$
- 600 N
- 80 kg