6. what is the formula for newtons second law of motion? choose the correct answer from the choices: a. (f =…

Explanation:

Step1: Recall Newton's Second Law

Newton's Second Law is given by the formula $F = ma$, where $F$ is the net - force, $m$ is the mass and $a$ is the acceleration.

Step2: Solve question 6

The formula for Newton's Second Law of Motion is $F=ma$. So the answer for question 6 is C. ($F = ma$).

Step3: Solve question 7

Given $F = 10N$ and $m=2kg$, using $F = ma$, we can find $a=\frac{F}{m}$. Substituting the values, $a=\frac{10N}{2kg}=5m/s^{2}$. So the answer for question 7 is B. ($5m/s^{2}$).

Step4: Solve question 8

According to $F = ma$, if $F$ increases and $m$ is constant, then $a$ increases. So the answer for question 8 is A. (Increasing the net force).

Step5: Solve question 9

Given $m = 4kg$ and $a = 3m/s^{2}$, using $F=ma$, we have $F=4kg\times3m/s^{2}=12N$. So the answer for question 9 is B. ($12N$).

Step6: Solve question 10

We know $F = ma$. If we want to find $a=\frac{F}{m}$. For example, if $F = 3N$ and $m = 4kg$, $a=\frac{3N}{4kg}=0.75m/s^{2}$. But without specific values for all options, we use the formula concept. If $F = 7N$ and $m = 1kg$, $a = 7m/s^{2}$; if $F = 12N$ and $m = 1kg$, $a = 12m/s^{2}$; if $F=1.33N$ and $m = 1kg$, $a = 1.33m/s^{2}$; if $F = 0.75N$ and $m = 1kg$, $a = 0.75m/s^{2}$. The relationship $a=\frac{F}{m}$ holds. But if we assume standard mass - force relationships, we know that when $F = 3N$ and $m = 4kg$, $a=\frac{3}{4}=0.75m/s^{2}$. So the answer for question 10 is D. ($0.75N$) considering the $F - m - a$ relationship.

Answer:

6. C. ($F = ma$)
7. B. ($5m/s^{2}$)
8. A. (Increasing the net force)
9. B. ($12N$)
10. D. ($0.75N$)