four students are training for their cross - country team at school. they were told to run for as long as…

Explanation:

Step1: Recall speed formula

Speed $v=\frac{d}{t}$, where $d$ is distance and $t$ is time.

Step2: Calculate Leslie's speed

Leslie's distance $d = 10.8$, time $t = 100$. So $v_{Leslie}=\frac{10.8}{100}=0.108$.

Step3: Calculate Bev's speed

Bev's distance $d = 6.5$, time $t = 55$. So $v_{Bev}=\frac{6.5}{55}\approx0.118$.

Step4: Calculate Chris's speed

Chris's distance $d = 1.2$, time $t = 120$. So $v_{Chris}=\frac{1.2}{120}=0.01$.

Step5: Calculate Dylan's speed

Dylan's distance $d = 3.6$, time $t = 60$. So $v_{Dylan}=\frac{3.6}{60}=0.06$.

Since no two - calculated speeds are equal, there is likely an error in the problem - setup or data. But if we assume the data is correct as given, we have calculated the speeds as above.

Answer:

There is no correct option as no two students have the same average speed based on the calculations.