a gas at 110 °c exerts a pressure of 225 torr in a sealed container. the temperature drops to 65 °c. what is…
a gas at 110 °c exerts a pressure of 225 torr in a sealed container. the temperature drops to 65 °c. what is the pressure of the gas at the cooler temperature? p = ? torr hint: be careful with the temperature units.
Answer
Explanation:
Step1: Convert temperatures to Kelvin
$T_1=110 + 273=383\ K$, $T_2=65 + 273 = 338\ K$
Step2: Apply Gay - Lussac's Law ($\frac{P_1}{T_1}=\frac{P_2}{T_2}$)
$P_2=\frac{P_1T_2}{T_1}$
Step3: Substitute values
$P_2=\frac{225\times338}{383}$ $P_2=\frac{76050}{383}\approx199\ torr$
Answer:
199