a gas is contained in a rigid container with a constant volume and an initial pressure of 2.0 atm. if the…

a gas is contained in a rigid container with a constant volume and an initial pressure of 2.0 atm. if the temperature increases from 310 k to 350 k, what is the final pressure?

a gas is contained in a rigid container with a constant volume and an initial pressure of 2.0 atm. if the temperature increases from 310 k to 350 k, what is the final pressure?

Answer

Explanation:

Step1: Identify the gas - law formula

For a constant - volume process, we use Gay - Lussac's law: $\frac{P_1}{T_1}=\frac{P_2}{T_2}$.

Step2: Rearrange the formula to solve for $P_2$

$P_2=\frac{T_2}{T_1}\times P_1$.

Step3: Substitute the given values

Given $P_1 = 2.0$ atm, $T_1=310$ K, and $T_2 = 350$ K. Then $P_2=\frac{350}{310}\times2.0$ atm.

Step4: Calculate the value of $P_2$

$P_2=\frac{350\times2.0}{310}\text{ atm}\approx2.26$ atm.

Answer:

$2.26$ atm