a gas exerts a pressure of 15.6 atm in a container with a volume of 3.09 l. what is the pressure when the…

a gas exerts a pressure of 15.6 atm in a container with a volume of 3.09 l. what is the pressure when the gas is transferred to a container with a volume of 1.895 l? p = ? atm assume that the number of moles and the temperature remain constant.

a gas exerts a pressure of 15.6 atm in a container with a volume of 3.09 l. what is the pressure when the gas is transferred to a container with a volume of 1.895 l? p = ? atm assume that the number of moles and the temperature remain constant.

Answer

Explanation:

Step1: Identify the relevant law

Boyle's law states $P_1V_1 = P_2V_2$ for a gas at constant temperature and number of moles.

Step2: Assign values

Let $P_1 = 15.6$ atm, $V_1=3.09$ L, $V_2 = 1.895$ L, and we need to find $P_2$.

Step3: Rearrange the formula

$P_2=\frac{P_1V_1}{V_2}$.

Step4: Substitute values

$P_2=\frac{15.6\times3.09}{1.895}$. $P_2=\frac{48.104}{1.895}$. $P_2 = 25.4$ atm.

Answer:

25.4 atm