a gas is heated from 298 k to 367 k while its volume changes from 2.5 l to 3.9 l. if the initial pressure of…

a gas is heated from 298 k to 367 k while its volume changes from 2.5 l to 3.9 l. if the initial pressure of the gas is 1.1 atm, what is the final pressure of the gas?\n0.57 atm\n0.87 atm\n1.4 atm\n2.1 atm
Answer
Answer:
B. 0.87 atm
Explanation:
Step1: Identify the combined - gas law formula
$$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$$
Step2: Rearrange the formula for $P_2$
$$P_2=\frac{P_1V_1T_2}{V_2T_1}$$
Step3: Substitute the given values
$P_1 = 1.1$ atm, $V_1=2.5$ L, $T_1 = 298$ K, $V_2 = 3.9$ L, $T_2=367$ K $$P_2=\frac{1.1\times2.5\times367}{3.9\times298}$$
Step4: Calculate the value of $P_2$
First, calculate the numerator: $1.1\times2.5\times367 = 1.1\times917.5=1009.25$ Then, calculate the denominator: $3.9\times298 = 1162.2$ $$P_2=\frac{1009.25}{1162.2}\approx0.87\text{ atm}$$