a gas has an initial volume of 2.4 l at a pressure of 1.5 atm and a temperature of 273 k. the pressure of…

a gas has an initial volume of 2.4 l at a pressure of 1.5 atm and a temperature of 273 k. the pressure of the gas increases to 4.5 atm, and the temperature of the gas increases to 313 k. what is the final volume of the gas? 0.70 l 0.92 l 6.3 l 8.3 l

a gas has an initial volume of 2.4 l at a pressure of 1.5 atm and a temperature of 273 k. the pressure of the gas increases to 4.5 atm, and the temperature of the gas increases to 313 k. what is the final volume of the gas? 0.70 l 0.92 l 6.3 l 8.3 l

Answer

Explanation:

Step1: Recall the combined - gas law

The combined - gas law is $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$, where $P_1$ is the initial pressure, $V_1$ is the initial volume, $T_1$ is the initial temperature, $P_2$ is the final pressure, $V_2$ is the final volume, and $T_2$ is the final temperature.

Step2: Rearrange the formula for $V_2$

$V_2=\frac{P_1V_1T_2}{T_1P_2}$

Step3: Substitute the given values

Given $P_1 = 1.5$ atm, $V_1=2.4$ L, $T_1 = 273$ K, $P_2 = 4.5$ atm, and $T_2 = 313$ K. $V_2=\frac{1.5\times2.4\times313}{273\times4.5}$ First, calculate the numerator: $1.5\times2.4\times313 = 1.5\times751.2=1126.8$. Then, calculate the denominator: $273\times4.5 = 1228.5$. $V_2=\frac{1126.8}{1228.5}\approx0.92$ L

Answer:

0.92 L