gas laws fact sheet\nideal gas law pv = nrt\nideal gas constant r = 8.314 l kpa/mol k or r = 0.0821 l…

gas laws fact sheet\nideal gas law pv = nrt\nideal gas constant r = 8.314 l kpa/mol k or r = 0.0821 l atm/mol k\nstandard atmospheric pressure 1 atm = 101.3 kpa\ncelsius to kelvin conversion k = °c + 273.15\nselect the correct answer\nthe gas in a sealed container has an absolute pressure of 125.4 kilopascals. if the air around the container is at a pressure of 99.8 kilopascals, what is the gauge pressure inside the container?\na. 1.5 kpa\nb. 24.1 kpa\nc. 25.6 kpa\nd. 112.6 kpa\ne. 225.2 kpa

gas laws fact sheet\nideal gas law pv = nrt\nideal gas constant r = 8.314 l kpa/mol k or r = 0.0821 l atm/mol k\nstandard atmospheric pressure 1 atm = 101.3 kpa\ncelsius to kelvin conversion k = °c + 273.15\nselect the correct answer\nthe gas in a sealed container has an absolute pressure of 125.4 kilopascals. if the air around the container is at a pressure of 99.8 kilopascals, what is the gauge pressure inside the container?\na. 1.5 kpa\nb. 24.1 kpa\nc. 25.6 kpa\nd. 112.6 kpa\ne. 225.2 kpa

Answer

Explanation:

Step1: Recall gauge - pressure formula

Gauge pressure $P_g$ is given by $P_g=P_{absolute}-P_{atmosphere}$.

Step2: Substitute given values

We have $P_{absolute} = 125.4$ kPa and $P_{atmosphere}=99.8$ kPa. So $P_g=125.4 - 99.8$.

Step3: Calculate the result

$P_g = 25.6$ kPa.

Answer:

C. 25.6 kPa