the gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 k. if the pressure decreases to 3.20…

the gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 k. if the pressure decreases to 3.20 atm, what is the temperature of the gas in kelvin?\n\n___ k\n\nyour answer should be rounded to three significant figures. do not include units in your answer.\n\nenter the answer

the gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 k. if the pressure decreases to 3.20 atm, what is the temperature of the gas in kelvin?\n\n___ k\n\nyour answer should be rounded to three significant figures. do not include units in your answer.\n\nenter the answer

Answer

Explanation:

Step1: Identify the gas - law formula

For a fixed amount of gas at constant volume, we use Gay - Lussac's law: $\frac{P_1}{T_1}=\frac{P_2}{T_2}$.

Step2: Rearrange the formula to solve for $T_2$

$T_2=\frac{P_2T_1}{P_1}$.

Step3: Substitute the given values

Given $P_1 = 3.90$ atm, $T_1=298$ K, and $P_2 = 3.20$ atm. Then $T_2=\frac{3.20\times298}{3.90}$.

Step4: Calculate the value of $T_2$

$T_2=\frac{953.6}{3.90}\approx244$ K.

Answer:

244