a gas in a rigid container at 25°c has a pressure of 0.96 atm. a change in temperature causes the pressure…

a gas in a rigid container at 25°c has a pressure of 0.96 atm. a change in temperature causes the pressure to increase to 1.25 atm. what is the new temperature of the gas? use $\frac{p_1}{t_1}=\frac{p_2}{t_2}$. -44.2°c 32.6°c 115°c 388°c

a gas in a rigid container at 25°c has a pressure of 0.96 atm. a change in temperature causes the pressure to increase to 1.25 atm. what is the new temperature of the gas? use $\frac{p_1}{t_1}=\frac{p_2}{t_2}$. -44.2°c 32.6°c 115°c 388°c

Answer

Explanation:

Step1: Convert initial temperature to Kelvin

$T_1=(25 + 273.15)\text{ K}=298.15\text{ K}$

Step2: Rearrange the formula for $T_2$

From $\frac{P_1}{T_1}=\frac{P_2}{T_2}$, we get $T_2=\frac{P_2T_1}{P_1}$

Step3: Substitute values

$P_1 = 0.96\text{ atm}$, $P_2=1.25\text{ atm}$, $T_1 = 298.15\text{ K}$ $T_2=\frac{1.25\text{ atm}\times298.15\text{ K}}{0.96\text{ atm}}\approx388\text{ K}$

Step4: Convert $T_2$ to Celsius

$T_2=(388 - 273.15)^{\circ}C\approx115^{\circ}C$

Answer:

$115^{\circ}C$