6. green light has a wavelength of 0.00000052 meters. the speed of light is 300,000,000 m/s. calculate the…
6. green light has a wavelength of 0.00000052 meters. the speed of light is 300,000,000 m/s. calculate the frequency of green light waves with this wavelength.\n7. what is the wavelength of a sound wave with a frequency of 220 hz if its speed is 340 m/s?\n8. what is the period of the sound wave above?\n9. ocean waves are hitting a beach at a rate of 3.5 hz.\n a. what is the period of the waves?\n b. calculate the speed of the waves if the distance between wave crests is 1.3 meters.\n10. the note a above middle c on a piano emits a sound wave with a wavelength of 0.77 meters.\n a. what is the frequency of the wave? use 340 m/s as the speed of the sound wave.\n b. what is the period of the sound wave?
Answer
6.
Explanation:
Step1: Identify the formula
The formula for the speed of a wave is $v = f\lambda$, where $v$ is the speed, $f$ is the frequency and $\lambda$ is the wavelength. We need to solve for $f$, so the rearranged equation is $f=\frac{v}{\lambda}$.
Step2: Substitute the given values
Given $v = 300000000$ m/s and $\lambda=0.00000052$ m. Then $f=\frac{300000000}{0.00000052}$.
Step3: Calculate the frequency
$f=\frac{3\times10^{8}}{5.2\times10^{- 7}}\approx5.77\times10^{14}$ Hz.
Answer:
$5.77\times10^{14}$ Hz
7.
Explanation:
Step1: Identify the formula
Using $v = f\lambda$, we solve for $\lambda$. The rearranged equation is $\lambda=\frac{v}{f}$.
Step2: Substitute the given values
Given $v = 340$ m/s and $f = 220$ Hz. Then $\lambda=\frac{340}{220}$.
Step3: Calculate the wavelength
$\lambda=\frac{340}{220}\approx1.55$ m.
Answer:
$1.55$ m
8.
Explanation:
Step1: Identify the formula
The relationship between period $T$ and frequency $f$ is $T=\frac{1}{f}$.
Step2: Substitute the given frequency
Since $f = 220$ Hz from problem 7, then $T=\frac{1}{220}$.
Step3: Calculate the period
$T\approx0.0045$ s.
Answer:
$0.0045$ s
9a.
Explanation:
Step1: Identify the formula
The relationship between period $T$ and frequency $f$ is $T=\frac{1}{f}$.
Step2: Substitute the given frequency
Given $f = 3.5$ Hz, then $T=\frac{1}{3.5}$.
Step3: Calculate the period
$T\approx0.29$ s.
Answer:
$0.29$ s
9b.
Explanation:
Step1: Identify the formula
The formula for the speed of a wave is $v = f\lambda$. Here, the distance between wave - crests is the wavelength $\lambda = 1.3$ m and $f = 3.5$ Hz.
Step2: Substitute the values
$v=3.5\times1.3$.
Step3: Calculate the speed
$v = 4.55$ m/s.
Answer:
$4.55$ m/s
10a.
Explanation:
Step1: Identify the formula
Using $v = f\lambda$, we solve for $f$. The rearranged equation is $f=\frac{v}{\lambda}$.
Step2: Substitute the given values
Given $v = 340$ m/s and $\lambda = 0.77$ m. Then $f=\frac{340}{0.77}$.
Step3: Calculate the frequency
$f\approx441.56$ Hz.
Answer:
$441.56$ Hz
10b.
Explanation:
Step1: Identify the formula
The relationship between period $T$ and frequency $f$ is $T=\frac{1}{f}$.
Step2: Substitute the calculated frequency
Since $f\approx441.56$ Hz from 10a, then $T=\frac{1}{441.56}$.
Step3: Calculate the period
$T\approx0.0023$ s.
Answer:
$0.0023$ s