the half - life of a radioactive kind of americium is 432 years. if you start with 814,816 grams of it, how…

the half - life of a radioactive kind of americium is 432 years. if you start with 814,816 grams of it, how much will be left after 2,160 years? grams
Answer
Explanation:
Step1: Calculate number of half - lives
The number of half - lives $n=\frac{2160}{432}=5$.
Step2: Use half - life formula
The formula for radioactive decay is $A = A_0\times(\frac{1}{2})^n$, where $A_0$ is the initial amount and $n$ is the number of half - lives. Here, $A_0 = 814816$ and $n = 5$. So $A=814816\times(\frac{1}{2})^5$.
Step3: Calculate the remaining amount
$A = 814816\times\frac{1}{32}=25463$.
Answer:
25463