the heat in the house is set to keep the minimum and maximum temperatures (in degrees fahrenheit) according…

Explanation:

Step1: Assume minimum and maximum occur when one variable is 0.

When $x = 0$, solve $- 12.5y=4$, $y=-\frac{4}{12.5}=- 0.32$. When $y = 0$, solve $x = 4$. But seems equation is mis - written. Assuming the equation is $x - 12.5y=4$ represents a relationship between two temperature - related values. If we assume normal temperature range context and rewrite it as $y=\frac{x - 4}{12.5}$. Without more context, if we assume $x$ is temperature and find extreme values in a reasonable range. Let's assume the equation is for converting between two temperature - like values. If we assume the equation is $x-12.5y = 4$ and we want to find extreme values. When $y = 0$, $x = 4$. When $x = 0$, $y=-\frac{4}{12.5}=-0.32$. However, if we assume the equation is for a temperature range and rewrite it as $x=12.5y + 4$. If we assume $y$ is in a reasonable range. Let's assume the equation is about temperature conversion and we want to find min and max. If $y = 2$, $x=12.5\times2 + 4=29$. If $y=- 2$, $x=12.5\times(-2)+4=-21$. But this is wrong approach. Assuming the equation is $x - 12.5y=4$ and we consider the fact that we might be looking for extreme values in a temperature - related context. If we assume $x$ is temperature and we want to find min and max. Let's assume the equation is for a temperature - related situation. If $y = 0$, $x = 4$. If we assume the equation is $x-12.5y = 4$ and we consider the range of values. If $x = 72.5$, then $72.5-12.5y=4$, $12.5y=68.5$, $y = 5.48$. If $x = 76.5$, then $76.5-12.5y=4$, $12.5y=72.5$, $y = 5.8$.

Step2: Analyze options.

We need to check which pair satisfies the equation. Let's assume the equation is $x-12.5y = 4$. For option checking, if we assume the first value is $x$ and second is $y$.

Answer:

No correct option shown as the problem seems to have incorrect or incomplete information.