the height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t - 16t². how…

the height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t - 16t². how long after launch does the projectile return to the ground?\n2 seconds\n4 seconds\n14 seconds\n16 seconds

the height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t - 16t². how long after launch does the projectile return to the ground?\n2 seconds\n4 seconds\n14 seconds\n16 seconds

Answer

Explanation:

Step1: 着地時の高さを設定

着地時、高さ$h = 0$です。したがって、$0 = 32t - 16t^{2}$という方程式を得ます。

Step2: 方程式を因数分解

$0 = 16t(2 - t)$と因数分解できます。

Step3: 解を求める

$16t = 0$または$2 - t = 0$となります。$16t = 0$の解は$t = 0$（発射時）、$2 - t = 0$の解は$t = 2$です。着地時の$t$は$2$秒です。

Answer:

A. 2 seconds