6. a hiker shouts toward a cliff that is a distance of 685 meters away. the shout is heard on the other side…

6. a hiker shouts toward a cliff that is a distance of 685 meters away. the shout is heard on the other side 4.00 s of time later.\na) what is the speed of sound?\nb) if the wavelength is.750 m, what is the frequency?\nc) what is the period of this vibration?

6. a hiker shouts toward a cliff that is a distance of 685 meters away. the shout is heard on the other side 4.00 s of time later.\na) what is the speed of sound?\nb) if the wavelength is.750 m, what is the frequency?\nc) what is the period of this vibration?

Answer

Explanation:

Step1: Calculate speed of sound

The sound travels to the cliff and back. So total distance (d = 2\times685\space m=1370\space m), time (t = 4.00\space s). Using formula (v=\frac{d}{t}), we have (v=\frac{1370}{4}).

Step2: Calculate frequency

Using formula (v = f\lambda), where (v) is speed of sound (from part a), (\lambda=0.750\space m). Then (f=\frac{v}{\lambda}).

Step3: Calculate period

Using formula (T=\frac{1}{f}), where (f) is frequency (from part b).

Answer:

a) (v=\frac{2\times685}{4}=342.5\space m/s) b) (f=\frac{342.5}{0.750}\approx456.7\space Hz) c) (T=\frac{1}{456.7}\approx0.0022\space s)