hiro rubs an inflated balloon on his hair, and his hair sticks to the balloon. as he moves the balloon away…

hiro rubs an inflated balloon on his hair, and his hair sticks to the balloon. as he moves the balloon away from his head, how does the electric force change?\nthe electric force increases because the balloon loses its charge.\nthe electric force increases because the distance increases.\nthe electric force decreases because the distance increases.\nthe electric force decreases because his hair loses its charge.

hiro rubs an inflated balloon on his hair, and his hair sticks to the balloon. as he moves the balloon away from his head, how does the electric force change?\nthe electric force increases because the balloon loses its charge.\nthe electric force increases because the distance increases.\nthe electric force decreases because the distance increases.\nthe electric force decreases because his hair loses its charge.

Answer

Answer:

The electric force decreases because the distance increases.

Explanation:

Step1: Recall Coulomb's law

The electric force $F$ between two charged - objects is given by $F = k\frac{q_1q_2}{r^2}$, where $k$ is a constant, $q_1$ and $q_2$ are the charges of the two objects, and $r$ is the distance between them.

Step2: Analyze the situation

When Hiro moves the balloon away from his head, the distance $r$ between the charged balloon and the charged hair increases. Since $q_1$ and $q_2$ remain relatively constant (no significant charge - loss in a short time), and $k$ is a constant, from the formula $F = k\frac{q_1q_2}{r^2}$, as $r$ increases, the value of $F$ decreases.