for his schools annual egg - drop contest, nick created a cushioned egg container made of cotton balls and…

for his schools annual egg - drop contest, nick created a cushioned egg container made of cotton balls and tin foil. in the first round, nick dropped his egg from the schools second floor balcony 18 feet above the ground, and the egg survived! which equation can you use to find how many seconds it took for the egg to hit the ground? if an object is dropped from s feet above the ground, the objects height in feet, h, t seconds after being dropped can be modeled by the formula h = - 16t² + s. 0 = - 16t² + 18 18 = - 16t² to the nearest tenth of a second, how long did it take for the egg to hit the ground? seconds

for his schools annual egg - drop contest, nick created a cushioned egg container made of cotton balls and tin foil. in the first round, nick dropped his egg from the schools second floor balcony 18 feet above the ground, and the egg survived! which equation can you use to find how many seconds it took for the egg to hit the ground? if an object is dropped from s feet above the ground, the objects height in feet, h, t seconds after being dropped can be modeled by the formula h = - 16t² + s. 0 = - 16t² + 18 18 = - 16t² to the nearest tenth of a second, how long did it take for the egg to hit the ground? seconds

Answer

Explanation:

Step1: Identify the correct equation

The formula for the height of a dropped - object is $h=-16t^{2}+s$. When the egg hits the ground, $h = 0$. The egg is dropped from $s = 18$ feet. Substituting these values into the formula gives $0=-16t^{2}+18$.

Step2: Solve the equation for $t$

First, rewrite the equation $0=-16t^{2}+18$ as $16t^{2}=18$. Then $t^{2}=\frac{18}{16}=\frac{9}{8}$. Taking the square - root of both sides, we get $t=\sqrt{\frac{9}{8}}$. Since $t\gt0$ (time cannot be negative in this context), $t=\frac{3}{\sqrt{8}}=\frac{3}{2\sqrt{2}}$. Rationalize the denominator: $t=\frac{3\sqrt{2}}{4}\approx\frac{3\times1.414}{4}=\frac{4.242}{4}=1.0605\approx1.1$.

Answer:

$1.1$