a hockey puck moves 28 meters southward, then 14 meters northward, and finally 4 meters southward. for this…

a hockey puck moves 28 meters southward, then 14 meters northward, and finally 4 meters southward. for this motion, what is the distance moved? distance (m) = what is the magnitude and direction of the displacement? magnitude (m) = dirn = (tap field to change.) check answers

a hockey puck moves 28 meters southward, then 14 meters northward, and finally 4 meters southward. for this motion, what is the distance moved? distance (m) = what is the magnitude and direction of the displacement? magnitude (m) = dirn = (tap field to change.) check answers

Answer

Explanation:

Step1: Calculate the distance

Distance is the total path length. Add up all the distances moved regardless of direction. $28 + 14+4$

Step2: Calculate the displacement magnitude

Displacement is the straight - line distance from the starting point to the ending point. Let south be positive and north be negative. Net displacement $d=28 - 14+4$.

Step3: Determine the displacement direction

Based on the sign of the net displacement. If positive, the direction is south; if negative, the direction is north.

Answer:

Distance (m) = 46 Magnitude (m) = 18 Dir'n = South