hw - 4 begin date: 9/11/2025 12:01:00 am due date: 9/28/2025 11:00:00 pm end date: 9/28/2025 11:00:00…

Explanation:

Step1: Calculate total resistance

The resistors are in series. The total resistance $R_{total}=R_1 + R_2+R_3+R_4+R_5$. Given $R_1 = 10\ k\Omega$, $R_2 = 24\ k\Omega$, $R_3 = 16\ k\Omega$, $R_4 = 10\ k\Omega$, $R_5 = 18\ k\Omega$. So $R_{total}=(10 + 24+16+10+18)\ k\Omega=78\ k\Omega$.

Step2: Calculate total voltage

The total voltage $V = V_1+V_2$, where $V_1 = 12.0\ V$ and $V_2 = 24.0\ V$. So $V=(12.0 + 24.0)\ V = 36.0\ V$.

Step3: Calculate current in the circuit

Using Ohm's law $I=\frac{V}{R}$, where $V$ is the total - voltage and $R$ is the total resistance. So $I=\frac{36.0\ V}{78\times10^{3}\ \Omega}\approx0.462\times10^{-3}\ A$.

Step4: Calculate voltage across $R_3$

Using Ohm's law $V_3 = I\times R_3$. Substitute $I = 0.462\times10^{-3}\ A$ and $R_3 = 16\times10^{3}\ \Omega$. Then $V_3=(0.462\times10^{-3}\ A)\times(16\times10^{3}\ \Omega)=7.39\ V$.

Answer:

$7.39$