an ideal gas exerts a pressure of 3 atm in a 3 l container. the container is at a temperature of 298 °c…
an ideal gas exerts a pressure of 3 atm in a 3 l container. the container is at a temperature of 298 °c. what will be the final pressure if the temperature stays the same and the volume of the container changes to 2 l?\n0.54 atm\n4.5 atm\n2 atm\n2.25 atm
Answer
Explanation:
Step1: Identify the relevant gas - law
Since the temperature is constant, we use Boyle's Law, which is $P_1V_1 = P_2V_2$.
Step2: Assign values to variables
$P_1 = 3$ atm, $V_1 = 3$ L, and $V_2 = 2$ L. We need to find $P_2$.
Step3: Rearrange the formula to solve for $P_2$
From $P_1V_1 = P_2V_2$, we can get $P_2=\frac{P_1V_1}{V_2}$.
Step4: Substitute the values
$P_2=\frac{3\ atm\times3\ L}{2\ L}=\frac{9}{2}= 4.5$ atm.
Answer:
4.5 atm