the ideal gas law is represented by $pv = nrt$. as volume is held constant and the temperature increases…

the ideal gas law is represented by $pv = nrt$. as volume is held constant and the temperature increases, how would the pressure be expected to change? (1 point)\nit would increase.\nit would decrease.\nit would remain constant.\nit would become zero.

the ideal gas law is represented by $pv = nrt$. as volume is held constant and the temperature increases, how would the pressure be expected to change? (1 point)\nit would increase.\nit would decrease.\nit would remain constant.\nit would become zero.

Answer

Explanation:

Step1: Rearrange ideal - gas law

Given $PV = nRT$, when $V$ is constant, we can write $P=\frac{nR}{V}T$. Here, $\frac{nR}{V}$ is a constant. Let $k = \frac{nR}{V}$, so $P = kT$.

Step2: Analyze the relationship

Since $k>0$ (as $n$, $R$, and $V$ are positive - valued physical quantities), when $T$ increases, $P$ will also increase because $P$ is directly proportional to $T$.

Answer:

It would increase.