an incident ray of light strikes water at an angle of 30°. the index of refraction of air is 1.0003, and the…

Explanation:

Step1: Recall Snell's Law

$n_1\sin\theta_1 = n_2\sin\theta_2$ where $n_1$ is the index of refraction of the incident - medium, $\theta_1$ is the angle of incidence, $n_2$ is the index of refraction of the refracting medium, and $\theta_2$ is the angle of refraction. Here, $n_1 = 1.0003$, $\theta_1=30^{\circ}$, and $n_2 = 1.33$. So, $1.0003\times\sin30^{\circ}=1.33\times\sin\theta_2$.

Step2: Solve for $\sin\theta_2$

$\sin\theta_2=\frac{1.0003\times\sin30^{\circ}}{1.33}$. Since $\sin30^{\circ}=\frac{1}{2}$, we have $\sin\theta_2=\frac{1.0003\times\frac{1}{2}}{1.33}=\frac{1.0003}{2\times1.33}=\frac{1.0003}{2.66}\approx0.376$.

Step3: Find $\theta_2$

$\theta_2=\sin^{- 1}(0.376)$. Using a calculator, $\theta_2\approx22^{\circ}$.

Answer:

$22^{\circ}$